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10231003113 = 36750900513
BaseRepresentation
bin10011000011101000…
…01011011111101001
3222102000102210211020
421201310023133221
5131423114044423
64411113523053
7511351043262
oct114164133751
928360383736
1010231003113
114380153081
121b96413489
13c7080b1c6
146d0ad5969
153ed2dd4e3
hex261d0b7e9

10231003113 has 8 divisors (see below), whose sum is σ = 13844939808. Its totient is φ = 6718867584.

The previous prime is 10231003091. The next prime is 10231003127. The reversal of 10231003113 is 31130013201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10231003113 - 232 = 5936035817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10231003092 and 10231003101.

It is not an unprimeable number, because it can be changed into a prime (10231003213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25450056 + ... + 25450457.

It is an arithmetic number, because the mean of its divisors is an integer number (1730617476).

Almost surely, 210231003113 is an apocalyptic number.

It is an amenable number.

10231003113 is a deficient number, since it is larger than the sum of its proper divisors (3613936695).

10231003113 is an equidigital number, since it uses as much as digits as its factorization.

10231003113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50900583.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10231003113 its reverse (31130013201), we get a palindrome (41361016314).

The spelling of 10231003113 in words is "ten billion, two hundred thirty-one million, three thousand, one hundred thirteen".

Divisors: 1 3 67 201 50900513 152701539 3410334371 10231003113