Base | Representation |
---|---|
bin | 11101110001101100001… |
… | …10111111110000011011 |
3 | 10121210211022000002022021 |
4 | 32320312012333300123 |
5 | 113230312131120443 |
6 | 2102002114235311 |
7 | 133626422453002 |
oct | 16706606776033 |
9 | 3553738002267 |
10 | 1023110020123 |
11 | 364997a30084 |
12 | 146351585b37 |
13 | 7562c099269 |
14 | 377397b3c39 |
15 | 1b9305599ed |
hex | ee361bfc1b |
1023110020123 has 4 divisors (see below), whose sum is σ = 1032671796120. Its totient is φ = 1013548244128.
The previous prime is 1023110020039. The next prime is 1023110020129. The reversal of 1023110020123 is 3210200113201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1023110020123 is a prime.
It is a super-2 number, since 2×10231100201232 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1023110020097 and 1023110020106.
It is not an unprimeable number, because it can be changed into a prime (1023110020129) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4780887838 + ... + 4780888051.
It is an arithmetic number, because the mean of its divisors is an integer number (258167949030).
Almost surely, 21023110020123 is an apocalyptic number.
1023110020123 is a deficient number, since it is larger than the sum of its proper divisors (9561775997).
1023110020123 is an equidigital number, since it uses as much as digits as its factorization.
1023110020123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9561775996.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1023110020123 its reverse (3210200113201), we get a palindrome (4233310133324).
The spelling of 1023110020123 in words is "one trillion, twenty-three billion, one hundred ten million, twenty thousand, one hundred twenty-three".
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