Base | Representation |
---|---|
bin | 11101110010010101001… |
… | …00100111111110011101 |
3 | 10121211201020000002210011 |
4 | 32321022210213332131 |
5 | 113232013023100412 |
6 | 2102100140443221 |
7 | 133641061531252 |
oct | 16711244477635 |
9 | 3554636002704 |
10 | 1023453331357 |
11 | 3650537a6976 |
12 | 146428549511 |
13 | 7568524cac2 |
14 | 3776d21d429 |
15 | 1b9507717a7 |
hex | ee4a927f9d |
1023453331357 has 2 divisors, whose sum is σ = 1023453331358. Its totient is φ = 1023453331356.
The previous prime is 1023453331279. The next prime is 1023453331379. The reversal of 1023453331357 is 7531333543201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 924109225636 + 99344105721 = 961306^2 + 315189^2 .
It is a cyclic number.
It is not a de Polignac number, because 1023453331357 - 211 = 1023453329309 is a prime.
It is a super-2 number, since 2×10234533313572 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1023453331657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511726665678 + 511726665679.
It is an arithmetic number, because the mean of its divisors is an integer number (511726665679).
Almost surely, 21023453331357 is an apocalyptic number.
It is an amenable number.
1023453331357 is a deficient number, since it is larger than the sum of its proper divisors (1).
1023453331357 is an equidigital number, since it uses as much as digits as its factorization.
1023453331357 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 340200, while the sum is 40.
Adding to 1023453331357 its reverse (7531333543201), we get a palindrome (8554786874558).
The spelling of 1023453331357 in words is "one trillion, twenty-three billion, four hundred fifty-three million, three hundred thirty-one thousand, three hundred fifty-seven".
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