Base | Representation |
---|---|
bin | 10111010010001000011111… |
… | …100110000011101001011111 |
3 | 111102120110020112111002111011 |
4 | 113102020133212003221133 |
5 | 101410220013411410333 |
6 | 1001442233501240051 |
7 | 30366144501243544 |
oct | 2722103746035137 |
9 | 442513215432434 |
10 | 102401140341343 |
11 | 2a6a0097148718 |
12 | b59a03a863027 |
13 | 451a50335232c |
14 | 1b403550a4bcb |
15 | bc8a4e3499cd |
hex | 5d221f983a5f |
102401140341343 has 2 divisors, whose sum is σ = 102401140341344. Its totient is φ = 102401140341342.
The previous prime is 102401140341301. The next prime is 102401140341359. The reversal of 102401140341343 is 343143041104201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102401140341343 is a prime.
It is a super-3 number, since 3×1024011403413433 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102401140641343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51200570170671 + 51200570170672.
It is an arithmetic number, because the mean of its divisors is an integer number (51200570170672).
Almost surely, 2102401140341343 is an apocalyptic number.
102401140341343 is a deficient number, since it is larger than the sum of its proper divisors (1).
102401140341343 is an equidigital number, since it uses as much as digits as its factorization.
102401140341343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 102401140341343 its reverse (343143041104201), we get a palindrome (445544181445544).
The spelling of 102401140341343 in words is "one hundred two trillion, four hundred one billion, one hundred forty million, three hundred forty-one thousand, three hundred forty-three".
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