Base | Representation |
---|---|
bin | 1001010100001000010000… |
… | …1110011001011000000011 |
3 | 1100021001220012022021111112 |
4 | 2111002010032121120003 |
5 | 2320243412110301011 |
6 | 33440502114033535 |
7 | 2104626642031334 |
oct | 225020416313003 |
9 | 40231805267445 |
10 | 10241420400131 |
11 | 32993a8905968 |
12 | 1194a32b788ab |
13 | 5939b989bcab |
14 | 27598a2c028b |
15 | 12b60992358b |
hex | 95084399603 |
10241420400131 has 2 divisors, whose sum is σ = 10241420400132. Its totient is φ = 10241420400130.
The previous prime is 10241420400089. The next prime is 10241420400161. The reversal of 10241420400131 is 13100402414201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10241420400131 - 218 = 10241420137987 is a prime.
It is a super-2 number, since 2×102414204001312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10241420400097 and 10241420400106.
It is not a weakly prime, because it can be changed into another prime (10241420400161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5120710200065 + 5120710200066.
It is an arithmetic number, because the mean of its divisors is an integer number (5120710200066).
Almost surely, 210241420400131 is an apocalyptic number.
10241420400131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10241420400131 is an equidigital number, since it uses as much as digits as its factorization.
10241420400131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 10241420400131 its reverse (13100402414201), we get a palindrome (23341822814332).
The spelling of 10241420400131 in words is "ten trillion, two hundred forty-one billion, four hundred twenty million, four hundred thousand, one hundred thirty-one".
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