Base | Representation |
---|---|
bin | 101111101101000011… |
… | …0001110000011000111 |
3 | 100210102110011102020221 |
4 | 1133122012032003013 |
5 | 3134300441430203 |
6 | 115021203405211 |
7 | 10254432531034 |
oct | 1373206160307 |
9 | 323373142227 |
10 | 102443311303 |
11 | 3a49a640043 |
12 | 17a30083807 |
13 | 9877a81188 |
14 | 4d5b75638b |
15 | 29e89b8abd |
hex | 17da18e0c7 |
102443311303 has 2 divisors, whose sum is σ = 102443311304. Its totient is φ = 102443311302.
The previous prime is 102443311297. The next prime is 102443311417. The reversal of 102443311303 is 303113344201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102443311303 - 221 = 102441214151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102443312303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51221655651 + 51221655652.
It is an arithmetic number, because the mean of its divisors is an integer number (51221655652).
Almost surely, 2102443311303 is an apocalyptic number.
102443311303 is a deficient number, since it is larger than the sum of its proper divisors (1).
102443311303 is an equidigital number, since it uses as much as digits as its factorization.
102443311303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 102443311303 its reverse (303113344201), we get a palindrome (405556655504).
The spelling of 102443311303 in words is "one hundred two billion, four hundred forty-three million, three hundred eleven thousand, three hundred three".
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