Base | Representation |
---|---|
bin | 1001010100110000001010… |
… | …1101000101111111111011 |
3 | 1100022002112201122201210102 |
4 | 2111030002231011333323 |
5 | 2320432331332423120 |
6 | 33445433051310015 |
7 | 2105456252543306 |
oct | 225140255057773 |
9 | 40262481581712 |
10 | 10252132311035 |
11 | 32a29a546509a |
12 | 1196b2244b30b |
13 | 594a05c09104 |
14 | 2762c4bdbb3d |
15 | 12ba35057d75 |
hex | 95302b45ffb |
10252132311035 has 12 divisors (see below), whose sum is σ = 12644046899568. Its totient is φ = 7980038117856.
The previous prime is 10252132311019. The next prime is 10252132311059. The reversal of 10252132311035 is 53011323125201.
It is not a de Polignac number, because 10252132311035 - 24 = 10252132311019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10252132310989 and 10252132311007.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 748870607 + ... + 748884296.
It is an arithmetic number, because the mean of its divisors is an integer number (1053670574964).
Almost surely, 210252132311035 is an apocalyptic number.
10252132311035 is a deficient number, since it is larger than the sum of its proper divisors (2391914588533).
10252132311035 is an equidigital number, since it uses as much as digits as its factorization.
10252132311035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1497754982 (or 1497754945 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 10252132311035 its reverse (53011323125201), we get a palindrome (63263455436236).
The spelling of 10252132311035 in words is "ten trillion, two hundred fifty-two billion, one hundred thirty-two million, three hundred eleven thousand, thirty-five".
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