Base | Representation |
---|---|
bin | 11101110101101000000… |
… | …00100001001001111111 |
3 | 10122000021111112112112111 |
4 | 32322310000201021333 |
5 | 113244123344014020 |
6 | 2102551450514451 |
7 | 134032651230625 |
oct | 16726400411177 |
9 | 3560244475474 |
10 | 1025222251135 |
11 | 365881262545 |
12 | 146840a35a27 |
13 | 758a787a2b4 |
14 | 3789a125515 |
15 | 1ba05bdad5a |
hex | eeb402127f |
1025222251135 has 16 divisors (see below), whose sum is σ = 1232407936800. Its totient is φ = 818751338496.
The previous prime is 1025222251129. The next prime is 1025222251159. The reversal of 1025222251135 is 5311522225201.
1025222251135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 1025222251135 - 25 = 1025222251103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1025222251097 and 1025222251106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8095936 + ... + 8221594.
It is an arithmetic number, because the mean of its divisors is an integer number (77025496050).
Almost surely, 21025222251135 is an apocalyptic number.
1025222251135 is a deficient number, since it is larger than the sum of its proper divisors (207185685665).
1025222251135 is a wasteful number, since it uses less digits than its factorization.
1025222251135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128490.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 1025222251135 its reverse (5311522225201), we get a palindrome (6336744476336).
The spelling of 1025222251135 in words is "one trillion, twenty-five billion, two hundred twenty-two million, two hundred fifty-one thousand, one hundred thirty-five".
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