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10253013151 = 103289734361
BaseRepresentation
bin10011000110010000…
…01001000010011111
3222110112212000220211
421203020021002133
5131444232410101
64413221353251
7512036113423
oct114310110237
928415760824
1010253013151
114391616597
121ba1868827
13c752464b4
146d39c4b83
154001d9c51
hex26320909f

10253013151 has 8 divisors (see below), whose sum is σ = 10356431904. Its totient is φ = 10149669120.

The previous prime is 10253013109. The next prime is 10253013217. The reversal of 10253013151 is 15131035201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10253013151 - 223 = 10244624543 is a prime.

It is a super-3 number, since 3×102530131513 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10253313151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 281211 + ... + 315571.

It is an arithmetic number, because the mean of its divisors is an integer number (1294553988).

Almost surely, 210253013151 is an apocalyptic number.

10253013151 is a deficient number, since it is larger than the sum of its proper divisors (103418753).

10253013151 is a wasteful number, since it uses less digits than its factorization.

10253013151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37361.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 10253013151 its reverse (15131035201), we get a palindrome (25384048352).

The spelling of 10253013151 in words is "ten billion, two hundred fifty-three million, thirteen thousand, one hundred fifty-one".

Divisors: 1 103 2897 34361 298391 3539183 99543817 10253013151