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1025313032545 = 5205062606509
BaseRepresentation
bin11101110101110010110…
…10110100100101100001
310122000111211100201012221
432322321122310211201
5113244320114020140
62103004452351041
7134035132656514
oct16727132644541
93560454321187
101025313032545
113659185279aa
12146867315481
13758c0613ac9
14378a81d6d7b
151ba0db6e14a
hexeeb96b4961

1025313032545 has 4 divisors (see below), whose sum is σ = 1230375639060. Its totient is φ = 820250426032.

The previous prime is 1025313032539. The next prime is 1025313032609. The reversal of 1025313032545 is 5452303135201.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 117879608896 + 907433423649 = 343336^2 + 952593^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1025313032545 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1025313032545.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102531303250 + ... + 102531303259.

It is an arithmetic number, because the mean of its divisors is an integer number (307593909765).

Almost surely, 21025313032545 is an apocalyptic number.

It is an amenable number.

1025313032545 is a deficient number, since it is larger than the sum of its proper divisors (205062606515).

1025313032545 is an equidigital number, since it uses as much as digits as its factorization.

1025313032545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 205062606514.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 1025313032545 its reverse (5452303135201), we get a palindrome (6477616167746).

The spelling of 1025313032545 in words is "one trillion, twenty-five billion, three hundred thirteen million, thirty-two thousand, five hundred forty-five".

Divisors: 1 5 205062606509 1025313032545