Base | Representation |
---|---|
bin | 1001010100110100100100… |
… | …1110100111010001111111 |
3 | 1100022012121012001010100121 |
4 | 2111031021032213101333 |
5 | 2320442242232100411 |
6 | 33450150315235411 |
7 | 2105530500526243 |
oct | 225151116472177 |
9 | 40265535033317 |
10 | 10253315503231 |
11 | 32a3452330989 |
12 | 11971b2748b67 |
13 | 594b64097138 |
14 | 276397dd4423 |
15 | 12baa3d73571 |
hex | 953493a747f |
10253315503231 has 2 divisors, whose sum is σ = 10253315503232. Its totient is φ = 10253315503230.
The previous prime is 10253315503199. The next prime is 10253315503271. The reversal of 10253315503231 is 13230551335201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10253315503231 - 25 = 10253315503199 is a prime.
It is a super-2 number, since 2×102533155032312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10253315503271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5126657751615 + 5126657751616.
It is an arithmetic number, because the mean of its divisors is an integer number (5126657751616).
Almost surely, 210253315503231 is an apocalyptic number.
10253315503231 is a deficient number, since it is larger than the sum of its proper divisors (1).
10253315503231 is an equidigital number, since it uses as much as digits as its factorization.
10253315503231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 34.
Adding to 10253315503231 its reverse (13230551335201), we get a palindrome (23483866838432).
The spelling of 10253315503231 in words is "ten trillion, two hundred fifty-three billion, three hundred fifteen million, five hundred three thousand, two hundred thirty-one".
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