Base | Representation |
---|---|
bin | 1001010100110100100100… |
… | …1110100111100001001111 |
3 | 1100022012121012001011200202 |
4 | 2111031021032213201033 |
5 | 2320442242232113312 |
6 | 33450150315244115 |
7 | 2105530500532136 |
oct | 225151116474117 |
9 | 40265535034622 |
10 | 10253315504207 |
11 | 32a3452331696 |
12 | 11971b274963b |
13 | 594b64097709 |
14 | 276397dd491d |
15 | 12baa3d739c2 |
hex | 953493a784f |
10253315504207 has 2 divisors, whose sum is σ = 10253315504208. Its totient is φ = 10253315504206.
The previous prime is 10253315504203. The next prime is 10253315504293. The reversal of 10253315504207 is 70240551335201.
10253315504207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10253315504207 - 22 = 10253315504203 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10253315504203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5126657752103 + 5126657752104.
It is an arithmetic number, because the mean of its divisors is an integer number (5126657752104).
Almost surely, 210253315504207 is an apocalyptic number.
10253315504207 is a deficient number, since it is larger than the sum of its proper divisors (1).
10253315504207 is an equidigital number, since it uses as much as digits as its factorization.
10253315504207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126000, while the sum is 38.
Adding to 10253315504207 its reverse (70240551335201), we get a palindrome (80493866839408).
The spelling of 10253315504207 in words is "ten trillion, two hundred fifty-three billion, three hundred fifteen million, five hundred four thousand, two hundred seven".
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