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1028119932397 = 1813156705087
BaseRepresentation
bin11101111011000001011…
…10010010110111101101
310122021202110000222221201
432331200232102313231
5113321042200314042
62104151202125501
7134164525143145
oct16754056226755
93567673028851
101028119932397
11367028998348
1214730b350891
1375c49cb87ac
1437a92cd5925
151bb252bd1b7
hexef60b92ded

1028119932397 has 4 divisors (see below), whose sum is σ = 1028176655616. Its totient is φ = 1028063209180.

The previous prime is 1028119932373. The next prime is 1028119932407. The reversal of 1028119932397 is 7932399118201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1028119932397 - 219 = 1028119408109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1028119936397) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28334413 + ... + 28370674.

It is an arithmetic number, because the mean of its divisors is an integer number (257044163904).

Almost surely, 21028119932397 is an apocalyptic number.

It is an amenable number.

1028119932397 is a deficient number, since it is larger than the sum of its proper divisors (56723219).

1028119932397 is an equidigital number, since it uses as much as digits as its factorization.

1028119932397 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56723218.

The product of its (nonzero) digits is 1469664, while the sum is 55.

The spelling of 1028119932397 in words is "one trillion, twenty-eight billion, one hundred nineteen million, nine hundred thirty-two thousand, three hundred ninety-seven".

Divisors: 1 18131 56705087 1028119932397