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102932706047 = 254940381603
BaseRepresentation
bin101111111011101000…
…1000111001011111111
3100211200120001020122012
41133313101013023333
53141301233043142
6115141525041435
710302524364623
oct1376721071377
9324616036565
10102932706047
113a720913606
1217b47b5627b
139925292072
144da674b183
152a26939882
hex17f74472ff

102932706047 has 4 divisors (see below), whose sum is σ = 102973090200. Its totient is φ = 102892321896.

The previous prime is 102932706043. The next prime is 102932706061. The reversal of 102932706047 is 740607239201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 102932706047 - 22 = 102932706043 is a prime.

It is a super-2 number, since 2×1029327060472 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 102932705995 and 102932706013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102932706043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20188253 + ... + 20193350.

It is an arithmetic number, because the mean of its divisors is an integer number (25743272550).

Almost surely, 2102932706047 is an apocalyptic number.

102932706047 is a deficient number, since it is larger than the sum of its proper divisors (40384153).

102932706047 is an equidigital number, since it uses as much as digits as its factorization.

102932706047 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40384152.

The product of its (nonzero) digits is 127008, while the sum is 41.

The spelling of 102932706047 in words is "one hundred two billion, nine hundred thirty-two million, seven hundred six thousand, forty-seven".

Divisors: 1 2549 40381603 102932706047