103002022113 has 4 divisors (see below), whose sum is σ = 137336029488. Its totient is φ = 68668014740.

The previous prime is 103002022093. The next prime is 103002022117. The reversal of 103002022113 is 311220200301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103002022113 - 2⁹ = 103002021601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103002022092 and 103002022101.

It is not an unprimeable number, because it can be changed into a prime (103002022117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17167003683 + ... + 17167003688.

It is an arithmetic number, because the mean of its divisors is an integer number (34334007372).

Almost surely, 2^103002022113 is an apocalyptic number.

It is an amenable number.

103002022113 is a deficient number, since it is larger than the sum of its proper divisors (34334007375).

103002022113 is an equidigital number, since it uses as much as digits as its factorization.

103002022113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34334007374.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 103002022113 its reverse (311220200301), we get a palindrome (414222222414).

The spelling of 103002022113 in words is "one hundred three billion, two million, twenty-two thousand, one hundred thirteen".