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10301011311053 is a prime number
BaseRepresentation
bin1001010111100110010000…
…0111101011100111001101
31100110202201012010012112102
42111321210013223213031
52322232432343423203
633524115210044445
72112136443310451
oct225714407534715
940422635105472
1010301011311053
1133116a837a281
1211a44a3a19725
135994c5654828
142788006c4661
1512ce462b9888
hex95e641eb9cd

10301011311053 has 2 divisors, whose sum is σ = 10301011311054. Its totient is φ = 10301011311052.

The previous prime is 10301011311013. The next prime is 10301011311131. The reversal of 10301011311053 is 35011311010301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9680480154409 + 620531156644 = 3111347^2 + 787738^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10301011311053 is a prime.

It is a super-2 number, since 2×103010113110532 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10301011311013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5150505655526 + 5150505655527.

It is an arithmetic number, because the mean of its divisors is an integer number (5150505655527).

Almost surely, 210301011311053 is an apocalyptic number.

It is an amenable number.

10301011311053 is a deficient number, since it is larger than the sum of its proper divisors (1).

10301011311053 is an equidigital number, since it uses as much as digits as its factorization.

10301011311053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 20.

Adding to 10301011311053 its reverse (35011311010301), we get a palindrome (45312322321354).

The spelling of 10301011311053 in words is "ten trillion, three hundred one billion, eleven million, three hundred eleven thousand, fifty-three".