10301011311121 has 4 divisors (see below), whose sum is σ = 10843169801200. Its totient is φ = 9758852821044.

The previous prime is 10301011311053. The next prime is 10301011311131. The reversal of 10301011311121 is 12111311010301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10301011311121 - 2²¹ = 10301009213969 is a prime.

It is a super-2 number, since 2×10301011311121² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10301011311095 and 10301011311104.

It is not an unprimeable number, because it can be changed into a prime (10301011311131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 271079245011 + ... + 271079245048.

It is an arithmetic number, because the mean of its divisors is an integer number (2710792450300).

Almost surely, 2^{10301011311121} is an apocalyptic number.

It is an amenable number.

10301011311121 is a deficient number, since it is larger than the sum of its proper divisors (542158490079).

10301011311121 is an equidigital number, since it uses as much as digits as its factorization.

10301011311121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 542158490078.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 10301011311121 its reverse (12111311010301), we get a palindrome (22412322321422).

The spelling of 10301011311121 in words is "ten trillion, three hundred one billion, eleven million, three hundred eleven thousand, one hundred twenty-one".