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1030102221319 is a prime number
BaseRepresentation
bin11101111110101101110…
…00001000001000000111
310122110212121001201010221
432333112320020020013
5113334122132040234
62105120013325211
7134264615261143
oct16772670101007
93573777051127
101030102221319
11367955938356
12147783196807
13761a48a1512
1437c002a0223
151bbde332eb4
hexefd6e08207

1030102221319 has 2 divisors, whose sum is σ = 1030102221320. Its totient is φ = 1030102221318.

The previous prime is 1030102221311. The next prime is 1030102221329. The reversal of 1030102221319 is 9131222010301.

1030102221319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1030102221319 - 23 = 1030102221311 is a prime.

It is a super-2 number, since 2×10301022213192 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1030102221293 and 1030102221302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1030102221311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515051110659 + 515051110660.

It is an arithmetic number, because the mean of its divisors is an integer number (515051110660).

Almost surely, 21030102221319 is an apocalyptic number.

1030102221319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030102221319 is an equidigital number, since it uses as much as digits as its factorization.

1030102221319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 1030102221319 in words is "one trillion, thirty billion, one hundred two million, two hundred twenty-one thousand, three hundred nineteen".