Search a number
-
+
10301023100167 is a prime number
BaseRepresentation
bin1001010111100110010011…
…0100101001110100000111
31100110202202000022011011021
42111321210310221310013
52322232443403201132
633524120310452011
72112136645441162
oct225714464516407
940422660264137
1010301023100167
113311703aa1648
1211a44a7964007
135994c7c21837
142788020b2ad9
1512ce47347997
hex95e64d29d07

10301023100167 has 2 divisors, whose sum is σ = 10301023100168. Its totient is φ = 10301023100166.

The previous prime is 10301023100143. The next prime is 10301023100183. The reversal of 10301023100167 is 76100132010301.

10301023100167 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10301023100167 - 215 = 10301023067399 is a prime.

It is a super-3 number, since 3×103010231001673 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10301023100107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5150511550083 + 5150511550084.

It is an arithmetic number, because the mean of its divisors is an integer number (5150511550084).

Almost surely, 210301023100167 is an apocalyptic number.

10301023100167 is a deficient number, since it is larger than the sum of its proper divisors (1).

10301023100167 is an equidigital number, since it uses as much as digits as its factorization.

10301023100167 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 10301023100167 its reverse (76100132010301), we get a palindrome (86401155110468).

The spelling of 10301023100167 in words is "ten trillion, three hundred one billion, twenty-three million, one hundred thousand, one hundred sixty-seven".