Base | Representation |
---|---|
bin | 10111011011000000011110… |
… | …101011011100010101101011 |
3 | 111111201202102102110121211022 |
4 | 113123000132223130111223 |
5 | 102000213022121111021 |
6 | 1003030334351523055 |
7 | 30461204602523555 |
oct | 2733003653342553 |
9 | 444652372417738 |
10 | 103011010332011 |
11 | 2a9057a69282a1 |
12 | b678282b2948b |
13 | 4562b86a7a1b2 |
14 | 1b61a8c1084d5 |
15 | bd98459441ab |
hex | 5db01eadc56b |
103011010332011 has 2 divisors, whose sum is σ = 103011010332012. Its totient is φ = 103011010332010.
The previous prime is 103011010331903. The next prime is 103011010332023. The reversal of 103011010332011 is 110233010110301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103011010332011 - 234 = 102993830462827 is a prime.
It is a super-2 number, since 2×1030110103320112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103011010332031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505505166005 + 51505505166006.
It is an arithmetic number, because the mean of its divisors is an integer number (51505505166006).
Almost surely, 2103011010332011 is an apocalyptic number.
103011010332011 is a deficient number, since it is larger than the sum of its proper divisors (1).
103011010332011 is an equidigital number, since it uses as much as digits as its factorization.
103011010332011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 103011010332011 its reverse (110233010110301), we get a palindrome (213244020442312).
The spelling of 103011010332011 in words is "one hundred three trillion, eleven billion, ten million, three hundred thirty-two thousand, eleven".
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