Base | Representation |
---|---|
bin | 10111011011000010011011… |
… | …010010110000010011010111 |
3 | 111111201221211010110011212021 |
4 | 113123002123102300103113 |
5 | 102000231312324342213 |
6 | 1003031322034234011 |
7 | 30461310450153205 |
oct | 2733023322602327 |
9 | 444657733404767 |
10 | 103013101012183 |
11 | 2a906679a8024a |
12 | b678767125907 |
13 | 456312ac53c5b |
14 | 1b61c09a4a075 |
15 | bd9919269d8d |
hex | 5db09b4b04d7 |
103013101012183 has 2 divisors, whose sum is σ = 103013101012184. Its totient is φ = 103013101012182.
The previous prime is 103013101012099. The next prime is 103013101012201. The reversal of 103013101012183 is 381210101310301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103013101012183 - 213 = 103013101003991 is a prime.
It is a super-2 number, since 2×1030131010121832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103013101013183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51506550506091 + 51506550506092.
It is an arithmetic number, because the mean of its divisors is an integer number (51506550506092).
Almost surely, 2103013101012183 is an apocalyptic number.
103013101012183 is a deficient number, since it is larger than the sum of its proper divisors (1).
103013101012183 is an equidigital number, since it uses as much as digits as its factorization.
103013101012183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 103013101012183 its reverse (381210101310301), we get a palindrome (484223202322484).
The spelling of 103013101012183 in words is "one hundred three trillion, thirteen billion, one hundred one million, twelve thousand, one hundred eighty-three".
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