Base | Representation |
---|---|
bin | 11101111110110001001… |
… | …10011010001110100111 |
3 | 10122110221121110111012002 |
4 | 32333120212122032213 |
5 | 113334202032200203 |
6 | 2105122525115515 |
7 | 134265416066621 |
oct | 16773046321647 |
9 | 3573847414162 |
10 | 1030131131303 |
11 | 3679701938aa |
12 | 1477909b8b9b |
13 | 761aa884311 |
14 | 37c04067c11 |
15 | 1bbe1b43d88 |
hex | efd899a3a7 |
1030131131303 has 2 divisors, whose sum is σ = 1030131131304. Its totient is φ = 1030131131302.
The previous prime is 1030131131269. The next prime is 1030131131329. The reversal of 1030131131303 is 3031311310301.
It is a strong prime.
It is an emirp because it is prime and its reverse (3031311310301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1030131131303 - 28 = 1030131131047 is a prime.
It is a super-2 number, since 2×10301311313032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1030133131303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515065565651 + 515065565652.
It is an arithmetic number, because the mean of its divisors is an integer number (515065565652).
Almost surely, 21030131131303 is an apocalyptic number.
1030131131303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1030131131303 is an equidigital number, since it uses as much as digits as its factorization.
1030131131303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 1030131131303 its reverse (3031311310301), we get a palindrome (4061442441604).
The spelling of 1030131131303 in words is "one trillion, thirty billion, one hundred thirty-one million, one hundred thirty-one thousand, three hundred three".
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