Base | Representation |
---|---|
bin | 10011001100000110… |
… | …00011011011101001 |
3 | 222120222001101111011 |
4 | 21212003003123221 |
5 | 132044303323423 |
6 | 4422131503521 |
7 | 513202435552 |
oct | 114603033351 |
9 | 28528041434 |
10 | 10302011113 |
11 | 4407242479 |
12 | 1bb6157ba1 |
13 | c82440784 |
14 | 6da2db329 |
15 | 404667b0d |
hex | 2660c36e9 |
10302011113 has 2 divisors, whose sum is σ = 10302011114. Its totient is φ = 10302011112.
The previous prime is 10302011107. The next prime is 10302011123. The reversal of 10302011113 is 31111020301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8254267609 + 2047743504 = 90853^2 + 45252^2 .
It is a cyclic number.
It is not a de Polignac number, because 10302011113 - 233 = 1712076521 is a prime.
It is a super-2 number, since 2×103020111132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10302011093 and 10302011102.
It is not a weakly prime, because it can be changed into another prime (10302011123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5151005556 + 5151005557.
It is an arithmetic number, because the mean of its divisors is an integer number (5151005557).
Almost surely, 210302011113 is an apocalyptic number.
It is an amenable number.
10302011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10302011113 is an equidigital number, since it uses as much as digits as its factorization.
10302011113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 10302011113 its reverse (31111020301), we get a palindrome (41413031414).
The spelling of 10302011113 in words is "ten billion, three hundred two million, eleven thousand, one hundred thirteen".
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