Base | Representation |
---|---|
bin | 101111111110010001… |
… | …0101111000111001111 |
3 | 100211220201120211010120 |
4 | 1133330202233013033 |
5 | 3141441412241421 |
6 | 115154410040023 |
7 | 10304650566036 |
oct | 1377442570717 |
9 | 324821524116 |
10 | 103021212111 |
11 | 3a766874514 |
12 | 17b71719013 |
13 | 993a71000c |
14 | 4db43c971d |
15 | 2a2e5bd8c6 |
hex | 17fc8af1cf |
103021212111 has 4 divisors (see below), whose sum is σ = 137361616152. Its totient is φ = 68680808072.
The previous prime is 103021212103. The next prime is 103021212143. The reversal of 103021212111 is 111212120301.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111212120301 = 3 ⋅37070706767.
It is a cyclic number.
It is not a de Polignac number, because 103021212111 - 23 = 103021212103 is a prime.
It is a super-2 number, since 2×1030212121112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103021217111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17170202016 + ... + 17170202021.
It is an arithmetic number, because the mean of its divisors is an integer number (34340404038).
Almost surely, 2103021212111 is an apocalyptic number.
103021212111 is a deficient number, since it is larger than the sum of its proper divisors (34340404041).
103021212111 is an equidigital number, since it uses as much as digits as its factorization.
103021212111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34340404040.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 103021212111 its reverse (111212120301), we get a palindrome (214233332412).
The spelling of 103021212111 in words is "one hundred three billion, twenty-one million, two hundred twelve thousand, one hundred eleven".
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