Base | Representation |
---|---|
bin | 11101111111000101010… |
… | …11000011010010000001 |
3 | 10122111101101110000100212 |
4 | 32333202223003102001 |
5 | 113340023312321233 |
6 | 2105151403123505 |
7 | 134302540344611 |
oct | 16774253032201 |
9 | 3574341400325 |
10 | 1030300120193 |
11 | 367a47615743 |
12 | 147819513595 |
13 | 762068a1346 |
14 | 37c1c696a41 |
15 | 1bc018c4a48 |
hex | efe2ac3481 |
1030300120193 has 2 divisors, whose sum is σ = 1030300120194. Its totient is φ = 1030300120192.
The previous prime is 1030300120163. The next prime is 1030300120207. The reversal of 1030300120193 is 3910210030301.
1030300120193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1017742004224 + 12558115969 = 1008832^2 + 112063^2 .
It is a cyclic number.
It is not a de Polignac number, because 1030300120193 - 210 = 1030300119169 is a prime.
It is not a weakly prime, because it can be changed into another prime (1030300120133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515150060096 + 515150060097.
It is an arithmetic number, because the mean of its divisors is an integer number (515150060097).
Almost surely, 21030300120193 is an apocalyptic number.
It is an amenable number.
1030300120193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1030300120193 is an equidigital number, since it uses as much as digits as its factorization.
1030300120193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 1030300120193 its reverse (3910210030301), we get a palindrome (4940510150494).
The spelling of 1030300120193 in words is "one trillion, thirty billion, three hundred million, one hundred twenty thousand, one hundred ninety-three".
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