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1030320043413 = 3343440014471
BaseRepresentation
bin11101111111000111101…
…11000011010110010101
310122111102202221012212220
432333203313003112111
5113340043412342123
62105153354132553
7134303201604033
oct16774367032625
93574382835786
101030320043413
11367a57893311
12147824121159
137620aa5882b
1437c211a1553
151bc0350cce3
hexefe3dc3595

1030320043413 has 4 divisors (see below), whose sum is σ = 1373760057888. Its totient is φ = 686880028940.

The previous prime is 1030320043399. The next prime is 1030320043439. The reversal of 1030320043413 is 3143400230301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1030320043413 - 216 = 1030319977877 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1030320043463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171720007233 + ... + 171720007238.

It is an arithmetic number, because the mean of its divisors is an integer number (343440014472).

Almost surely, 21030320043413 is an apocalyptic number.

It is an amenable number.

1030320043413 is a deficient number, since it is larger than the sum of its proper divisors (343440014475).

1030320043413 is an equidigital number, since it uses as much as digits as its factorization.

1030320043413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 343440014474.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 1030320043413 its reverse (3143400230301), we get a palindrome (4173720273714).

The spelling of 1030320043413 in words is "one trillion, thirty billion, three hundred twenty million, forty-three thousand, four hundred thirteen".

Divisors: 1 3 343440014471 1030320043413