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10306132131 = 33435377377
BaseRepresentation
bin10011001100100101…
…10001100010100011
3222121020210202110110
421212102301202203
5132101332212011
64422400102403
7513252451311
oct114622614243
928536722413
1010306132131
1144095a7679
121bb7604a03
13c83254449
146daa910b1
15404bcdba6
hex2664b18a3

10306132131 has 4 divisors (see below), whose sum is σ = 13741509512. Its totient is φ = 6870754752.

The previous prime is 10306132127. The next prime is 10306132147. The reversal of 10306132131 is 13123160301.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10306132131 - 22 = 10306132127 is a prime.

It is a super-2 number, since 2×103061321312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10306132098 and 10306132107.

It is not an unprimeable number, because it can be changed into a prime (10306132121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1717688686 + ... + 1717688691.

It is an arithmetic number, because the mean of its divisors is an integer number (3435377378).

Almost surely, 210306132131 is an apocalyptic number.

10306132131 is a deficient number, since it is larger than the sum of its proper divisors (3435377381).

10306132131 is an equidigital number, since it uses as much as digits as its factorization.

10306132131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3435377380.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 10306132131 its reverse (13123160301), we get a palindrome (23429292432).

The spelling of 10306132131 in words is "ten billion, three hundred six million, one hundred thirty-two thousand, one hundred thirty-one".

Divisors: 1 3 3435377377 10306132131