Base | Representation |
---|---|
bin | 10111011100010011011101… |
… | …011100000111111001110011 |
3 | 111112001021101221102022221122 |
4 | 113130103131130013321303 |
5 | 102003143011142012243 |
6 | 1003135311533212455 |
7 | 30500510561246234 |
oct | 2734233534077163 |
9 | 445037357368848 |
10 | 103100110110323 |
11 | 2a93a569385517 |
12 | b6915aa33112b |
13 | 456b3b6228c01 |
14 | 1b6610162d08b |
15 | bdbd0cc4d668 |
hex | 5dc4dd707e73 |
103100110110323 has 2 divisors, whose sum is σ = 103100110110324. Its totient is φ = 103100110110322.
The previous prime is 103100110110301. The next prime is 103100110110341. The reversal of 103100110110323 is 323011011001301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103100110110323 is a prime.
It is not a weakly prime, because it can be changed into another prime (103100110160323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51550055055161 + 51550055055162.
It is an arithmetic number, because the mean of its divisors is an integer number (51550055055162).
Almost surely, 2103100110110323 is an apocalyptic number.
103100110110323 is a deficient number, since it is larger than the sum of its proper divisors (1).
103100110110323 is an equidigital number, since it uses as much as digits as its factorization.
103100110110323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 103100110110323 its reverse (323011011001301), we get a palindrome (426111121111624).
The spelling of 103100110110323 in words is "one hundred three trillion, one hundred billion, one hundred ten million, one hundred ten thousand, three hundred twenty-three".
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