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103100202021312 = 26321971572757773
BaseRepresentation
bin10111011100010011100010…
…111010101111000111000000
3111112001021122100100220010100
4113130103202322233013000
5102003143203204140222
61003135325015202400
730500513055421266
oct2734234272570700
9445037570326110
10103100202021312
112a93a606251611
12b691615076400
13456b3cc299902
141b6610d916436
15bdbd15d564ac
hex5dc4e2eaf1c0

103100202021312 has 168 divisors, whose sum is σ = 297042233057856. Its totient is φ = 34189517666304.

The previous prime is 103100202021281. The next prime is 103100202021343. The reversal of 103100202021312 is 213120202001301.

103100202021312 is a `hidden beast` number, since 1 + 0 + 310 + 0 + 2 + 0 + 20 + 21 + 312 = 666.

It is an interprime number because it is at equal distance from previous prime (103100202021281) and next prime (103100202021343).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1784545258 + ... + 1784603030.

Almost surely, 2103100202021312 is an apocalyptic number.

103100202021312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 103100202021312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (148521116528928).

103100202021312 is an abundant number, since it is smaller than the sum of its proper divisors (193942031036544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103100202021312 is a wasteful number, since it uses less digits than its factorization.

103100202021312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73715 (or 73702 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 103100202021312 its reverse (213120202001301), we get a palindrome (316220404022613).

The spelling of 103100202021312 in words is "one hundred three trillion, one hundred billion, two hundred two million, twenty-one thousand, three hundred twelve".