Base | Representation |
---|---|
bin | 10111011100010011101010… |
… | …100011110100100101000011 |
3 | 111112001021222021121200022012 |
4 | 113130103222203310211003 |
5 | 102003143434014412011 |
6 | 1003135345435203135 |
7 | 30500516203250621 |
oct | 2734235243644503 |
9 | 445037867550265 |
10 | 103100330232131 |
11 | 2a93a671661271 |
12 | b69164bba64ab |
13 | 456b41ca09bbb |
14 | 1b6612296c511 |
15 | bdbd2222ea8b |
hex | 5dc4ea8f4943 |
103100330232131 has 2 divisors, whose sum is σ = 103100330232132. Its totient is φ = 103100330232130.
The previous prime is 103100330232079. The next prime is 103100330232167. The reversal of 103100330232131 is 131232033001301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103100330232131 - 222 = 103100326037827 is a prime.
It is a super-2 number, since 2×1031003302321312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103100330232097 and 103100330232106.
It is not a weakly prime, because it can be changed into another prime (103100330232631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51550165116065 + 51550165116066.
It is an arithmetic number, because the mean of its divisors is an integer number (51550165116066).
Almost surely, 2103100330232131 is an apocalyptic number.
103100330232131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103100330232131 is an equidigital number, since it uses as much as digits as its factorization.
103100330232131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 103100330232131 its reverse (131232033001301), we get a palindrome (234332363233432).
The spelling of 103100330232131 in words is "one hundred three trillion, one hundred billion, three hundred thirty million, two hundred thirty-two thousand, one hundred thirty-one".
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