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1031011212113 = 5944813899747
BaseRepresentation
bin11110000000011010000…
…11101001101101010001
310122120012221111020002122
433000031003221231101
5113343002332241423
62105350124224025
7134326263464111
oct17001503515521
93576187436078
101031011212113
11368281a50613
1214799769b015
13762bacc52ac
1437c88cbb041
151bc440388c8
hexf00d0e9b51

1031011212113 has 8 divisors (see below), whose sum is σ = 1048720232160. Its totient is φ = 1013310000640.

The previous prime is 1031011212083. The next prime is 1031011212131. The reversal of 1031011212113 is 3112121101301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1031011212113 - 220 = 1031010163537 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1031011212091 and 1031011212100.

It is not an unprimeable number, because it can be changed into a prime (1031011212163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1685495 + ... + 2214252.

It is an arithmetic number, because the mean of its divisors is an integer number (131090029020).

Almost surely, 21031011212113 is an apocalyptic number.

It is an amenable number.

1031011212113 is a deficient number, since it is larger than the sum of its proper divisors (17709020047).

1031011212113 is an equidigital number, since it uses as much as digits as its factorization.

1031011212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3904287.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1031011212113 its reverse (3112121101301), we get a palindrome (4143132313414).

The spelling of 1031011212113 in words is "one trillion, thirty-one billion, eleven million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 59 4481 264379 3899747 230085073 17474766307 1031011212113