Base | Representation |
---|---|
bin | 110000000000101101… |
… | …1001111000111100011 |
3 | 100212010102201210021101 |
4 | 1200001123033013203 |
5 | 3142123400212011 |
6 | 115210453535231 |
7 | 10306664106646 |
oct | 1400133170743 |
9 | 325112653241 |
10 | 103103132131 |
11 | 3a7a903720a |
12 | 17b95044517 |
13 | 99516932bc |
14 | 4dc1231a5d |
15 | 2a368a12c1 |
hex | 18016cf1e3 |
103103132131 has 2 divisors, whose sum is σ = 103103132132. Its totient is φ = 103103132130.
The previous prime is 103103132117. The next prime is 103103132147. The reversal of 103103132131 is 131231301301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103103132131 - 211 = 103103130083 is a prime.
It is a super-2 number, since 2×1031031321312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103103132099 and 103103132108.
It is not a weakly prime, because it can be changed into another prime (103103132101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51551566065 + 51551566066.
It is an arithmetic number, because the mean of its divisors is an integer number (51551566066).
Almost surely, 2103103132131 is an apocalyptic number.
103103132131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103103132131 is an equidigital number, since it uses as much as digits as its factorization.
103103132131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 103103132131 its reverse (131231301301), we get a palindrome (234334433432).
The spelling of 103103132131 in words is "one hundred three billion, one hundred three million, one hundred thirty-two thousand, one hundred thirty-one".
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