Base | Representation |
---|---|
bin | 110000000000101101… |
… | …1111111011101010011 |
3 | 100212010110002211212201 |
4 | 1200001123333131103 |
5 | 3142123423031011 |
6 | 115210502104031 |
7 | 10306665563134 |
oct | 1400133773523 |
9 | 325113084781 |
10 | 103103330131 |
11 | 3a7a9161a4a |
12 | 17b9511b017 |
13 | 9951732469 |
14 | 4dc1283c8b |
15 | 2a368decc1 |
hex | 18016ff753 |
103103330131 has 2 divisors, whose sum is σ = 103103330132. Its totient is φ = 103103330130.
The previous prime is 103103330119. The next prime is 103103330299. The reversal of 103103330131 is 131033301301.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103103330131 - 231 = 100955846483 is a prime.
It is a super-2 number, since 2×1031033301312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103103330099 and 103103330108.
It is not a weakly prime, because it can be changed into another prime (103103330111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51551665065 + 51551665066.
It is an arithmetic number, because the mean of its divisors is an integer number (51551665066).
Almost surely, 2103103330131 is an apocalyptic number.
103103330131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103103330131 is an equidigital number, since it uses as much as digits as its factorization.
103103330131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 103103330131 its reverse (131033301301), we get a palindrome (234136631432).
The spelling of 103103330131 in words is "one hundred three billion, one hundred three million, three hundred thirty thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •