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103110122321197 is a prime number
BaseRepresentation
bin10111011100011100110010…
…001101101011010100101101
3111112002020020201011100020121
4113130130302031223110231
5102003324012303234242
61003144045233444541
730501313644526345
oct2734346215532455
9445066221140217
10103110122321197
112a943836a7a762
12b693523410751
13456c320600344
141b667b124dd25
15bdc1e6c1e667
hex5dc73236b52d

103110122321197 has 2 divisors, whose sum is σ = 103110122321198. Its totient is φ = 103110122321196.

The previous prime is 103110122321111. The next prime is 103110122321249. The reversal of 103110122321197 is 791123221011301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98278790836356 + 4831331484841 = 9913566^2 + 2198029^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103110122321197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103110122121197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51555061160598 + 51555061160599.

It is an arithmetic number, because the mean of its divisors is an integer number (51555061160599).

Almost surely, 2103110122321197 is an apocalyptic number.

It is an amenable number.

103110122321197 is a deficient number, since it is larger than the sum of its proper divisors (1).

103110122321197 is an equidigital number, since it uses as much as digits as its factorization.

103110122321197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4536, while the sum is 34.

Adding to 103110122321197 its reverse (791123221011301), we get a palindrome (894233343332498).

The spelling of 103110122321197 in words is "one hundred three trillion, one hundred ten billion, one hundred twenty-two million, three hundred twenty-one thousand, one hundred ninety-seven".