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103111210312973 is a prime number
BaseRepresentation
bin10111011100011101110011…
…000100000010010100001101
3111112002100001112102001101022
4113130131303010002110031
5102003333224320003343
61003144345221123525
730501352625360132
oct2734356304022415
9445070045361338
10103111210312973
112a944245133015
12b6937878595a5
13456c464b38365
141b66875944589
15bdc25c4d2568
hex5dc77310250d

103111210312973 has 2 divisors, whose sum is σ = 103111210312974. Its totient is φ = 103111210312972.

The previous prime is 103111210312927. The next prime is 103111210313131. The reversal of 103111210312973 is 379213012111301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85513629980164 + 17597580332809 = 9247358^2 + 4194947^2 .

It is a cyclic number.

It is not a de Polignac number, because 103111210312973 - 218 = 103111210050829 is a prime.

It is a super-2 number, since 2×1031112103129732 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103111210315973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51555605156486 + 51555605156487.

It is an arithmetic number, because the mean of its divisors is an integer number (51555605156487).

Almost surely, 2103111210312973 is an apocalyptic number.

It is an amenable number.

103111210312973 is a deficient number, since it is larger than the sum of its proper divisors (1).

103111210312973 is an equidigital number, since it uses as much as digits as its factorization.

103111210312973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 35.

The spelling of 103111210312973 in words is "one hundred three trillion, one hundred eleven billion, two hundred ten million, three hundred twelve thousand, nine hundred seventy-three".