10311123131 has 2 divisors, whose sum is σ = 10311123132. Its totient is φ = 10311123130.

The previous prime is 10311123113. The next prime is 10311123143. The reversal of 10311123131 is 13132111301.

10311123131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (10311123113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13132111301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10311123131 - 2²⁶ = 10244014267 is a prime.

It is a super-2 number, since 2×10311123131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10311123161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155561565 + 5155561566.

It is an arithmetic number, because the mean of its divisors is an integer number (5155561566).

Almost surely, 2^10311123131 is an apocalyptic number.

10311123131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10311123131 is an equidigital number, since it uses as much as digits as its factorization.

10311123131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10311123131 its reverse (13132111301), we get a palindrome (23443234432).

The spelling of 10311123131 in words is "ten billion, three hundred eleven million, one hundred twenty-three thousand, one hundred thirty-one".