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1031113000000 = 265623127353
BaseRepresentation
bin11110000000100110001…
…11111100010001000000
310122120111001000120211101
433000103013330101000
5113343204412000000
62105404202024144
7134331640613566
oct17002307742100
93576431016741
101031113000000
11368324453336
12147a057a8054
1376306113805
1437c98615a36
151bc4ce42e6a
hexf0131fc440

1031113000000 has 392 divisors, whose sum is σ = 2697445472256. Its totient is φ = 390297600000.

The previous prime is 1031112999979. The next prime is 1031113000009. The reversal of 1031113000000 is 3111301.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is not an unprimeable number, because it can be changed into a prime (1031113000009) by changing a digit.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 2920999824 + ... + 2921000176.

Almost surely, 21031113000000 is an apocalyptic number.

1031113000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1031113000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1348722736128).

1031113000000 is an abundant number, since it is smaller than the sum of its proper divisors (1666332472256).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1031113000000 is an frugal number, since it uses more digits than its factorization.

1031113000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 545 (or 510 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 1031113000000 its reverse (3111301), we get a palindrome (1031116111301).

The spelling of 1031113000000 in words is "one trillion, thirty-one billion, one hundred thirteen million", and thus it is an aban number.