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103112103131 = 170960334759
BaseRepresentation
bin110000000000111110…
…1011101010011011011
3100212011001121120011122
41200001331131103123
53142133144300011
6115211414115455
710310133262322
oct1400175352333
9325131546148
10103112103131
113a803104264
1217b9804bb8b
1399534b469b
144dc24c90b9
152a375743db
hex1801f5d4db

103112103131 has 4 divisors (see below), whose sum is σ = 103172439600. Its totient is φ = 103051766664.

The previous prime is 103112103119. The next prime is 103112103191. The reversal of 103112103131 is 131301211301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103112103131 is a prime.

It is a super-2 number, since 2×1031121031312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103112103191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30165671 + ... + 30169088.

It is an arithmetic number, because the mean of its divisors is an integer number (25793109900).

Almost surely, 2103112103131 is an apocalyptic number.

103112103131 is a deficient number, since it is larger than the sum of its proper divisors (60336469).

103112103131 is an equidigital number, since it uses as much as digits as its factorization.

103112103131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60336468.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 103112103131 its reverse (131301211301), we get a palindrome (234413314432).

The spelling of 103112103131 in words is "one hundred three billion, one hundred twelve million, one hundred three thousand, one hundred thirty-one".

Divisors: 1 1709 60334759 103112103131