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1031121132017 is a prime number
BaseRepresentation
bin11110000000100111001…
…10111101100111110001
310122120111121022201212012
433000103212331213301
5113343214002211032
62105405052212305
7134332100003234
oct17002346754761
93576447281765
101031121132017
11368328aa8009
12147a0846a095
1376307a00062
1437c9973141b
151bc4d9ec6b2
hexf0139bd9f1

1031121132017 has 2 divisors, whose sum is σ = 1031121132018. Its totient is φ = 1031121132016.

The previous prime is 1031121132007. The next prime is 1031121132049. The reversal of 1031121132017 is 7102311211301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 895173330496 + 135947801521 = 946136^2 + 368711^2 .

It is a cyclic number.

It is not a de Polignac number, because 1031121132017 - 234 = 1013941262833 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1031121131983 and 1031121132001.

It is not a weakly prime, because it can be changed into another prime (1031121132007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515560566008 + 515560566009.

It is an arithmetic number, because the mean of its divisors is an integer number (515560566009).

Almost surely, 21031121132017 is an apocalyptic number.

It is an amenable number.

1031121132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031121132017 is an equidigital number, since it uses as much as digits as its factorization.

1031121132017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 1031121132017 its reverse (7102311211301), we get a palindrome (8133432343318).

The spelling of 1031121132017 in words is "one trillion, thirty-one billion, one hundred twenty-one million, one hundred thirty-two thousand, seventeen".