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103113113 = 131787123
BaseRepresentation
bin1100010010101…
…10000110011001
321012000200121012
412021112012121
5202344104423
614122023305
72361306215
oct611260631
9235020535
10103113113
1153228454
122a647b35
131849379c
14d9a1945
1590bc078
hex6256199

103113113 has 4 divisors (see below), whose sum is σ = 103900368. Its totient is φ = 102325860.

The previous prime is 103113107. The next prime is 103113137. The reversal of 103113113 is 311311301.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103113113 - 28 = 103112857 is a prime.

It is a super-4 number, since 4×1031131134 (a number of 33 digits) contains 4444 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (103113103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393431 + ... + 393692.

It is an arithmetic number, because the mean of its divisors is an integer number (25975092).

Almost surely, 2103113113 is an apocalyptic number.

It is an amenable number.

103113113 is a deficient number, since it is larger than the sum of its proper divisors (787255).

103113113 is an equidigital number, since it uses as much as digits as its factorization.

103113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 787254.

The product of its (nonzero) digits is 27, while the sum is 14.

The square root of 103113113 is about 10154.4627135068. The cubic root of 103113113 is about 468.9263450753.

Adding to 103113113 its reverse (311311301), we get a palindrome (414424414).

The spelling of 103113113 in words is "one hundred three million, one hundred thirteen thousand, one hundred thirteen".

Divisors: 1 131 787123 103113113