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103113120 = 25351159331
BaseRepresentation
bin1100010010101…
…10000110100000
321012000200121110
412021112012200
5202344104440
614122023320
72361306225
oct611260640
9235020543
10103113120
1153228460
122a647b40
13184937a6
14d9a194c
1590bc080
hex62561a0

103113120 has 192 divisors, whose sum is σ = 361428480. Its totient is φ = 24499200.

The previous prime is 103113107. The next prime is 103113137. The reversal of 103113120 is 21311301.

It is a super-2 number, since 2×1031131202 = 21264631032268800, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 103113096 and 103113105.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 311355 + ... + 311685.

It is an arithmetic number, because the mean of its divisors is an integer number (1882440).

Almost surely, 2103113120 is an apocalyptic number.

103113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 103113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (180714240).

103113120 is an abundant number, since it is smaller than the sum of its proper divisors (258315360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103113120 is a wasteful number, since it uses less digits than its factorization.

103113120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 419 (or 411 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

The square root of 103113120 is about 10154.4630581828. The cubic root of 103113120 is about 468.9263556866.

Adding to 103113120 its reverse (21311301), we get a palindrome (124424421).

It can be divided in two parts, 10311 and 3120, that added together give a palindrome (13431).

The spelling of 103113120 in words is "one hundred three million, one hundred thirteen thousand, one hundred twenty".