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103113132302353 is a prime number
BaseRepresentation
bin10111011100011111100101…
…100111110110000000010001
3111112002112000110222020011011
4113130133211213312000101
5102003401143332133403
61003145304040050521
730501451354122535
oct2734374547660021
9445075013866134
10103113132302353
112a945041038098
12b694023463a41
13456c6b009a994
141b669b8cd3bc5
15bdc3210d5a6d
hex5dc7e59f6011

103113132302353 has 2 divisors, whose sum is σ = 103113132302354. Its totient is φ = 103113132302352.

The previous prime is 103113132302281. The next prime is 103113132302407. The reversal of 103113132302353 is 353203231311301.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90114922580544 + 12998209721809 = 9492888^2 + 3605303^2 .

It is a cyclic number.

It is not a de Polignac number, because 103113132302353 - 221 = 103113130205201 is a prime.

It is not a weakly prime, because it can be changed into another prime (103113132312353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51556566151176 + 51556566151177.

It is an arithmetic number, because the mean of its divisors is an integer number (51556566151177).

Almost surely, 2103113132302353 is an apocalyptic number.

It is an amenable number.

103113132302353 is a deficient number, since it is larger than the sum of its proper divisors (1).

103113132302353 is an equidigital number, since it uses as much as digits as its factorization.

103113132302353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14580, while the sum is 31.

Adding to 103113132302353 its reverse (353203231311301), we get a palindrome (456316363613654).

The spelling of 103113132302353 in words is "one hundred three trillion, one hundred thirteen billion, one hundred thirty-two million, three hundred two thousand, three hundred fifty-three".