Base | Representation |
---|---|
bin | 10011001101001101… |
… | …00100111000010001 |
3 | 222121121120111012112 |
4 | 21212212210320101 |
5 | 132104144320103 |
6 | 4423103235105 |
7 | 513344541425 |
oct | 114646447021 |
9 | 28547514175 |
10 | 10311323153 |
11 | 441152277a |
12 | 1bb92a8a95 |
13 | c84351161 |
14 | 6db642b85 |
15 | 4053a6cd8 |
hex | 2669a4e11 |
10311323153 has 2 divisors, whose sum is σ = 10311323154. Its totient is φ = 10311323152.
The previous prime is 10311323119. The next prime is 10311323179. The reversal of 10311323153 is 35132311301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9815459329 + 495863824 = 99073^2 + 22268^2 .
It is an emirp because it is prime and its reverse (35132311301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10311323153 - 220 = 10310274577 is a prime.
It is a super-2 number, since 2×103113231532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10311323653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155661576 + 5155661577.
It is an arithmetic number, because the mean of its divisors is an integer number (5155661577).
Almost surely, 210311323153 is an apocalyptic number.
It is an amenable number.
10311323153 is a deficient number, since it is larger than the sum of its proper divisors (1).
10311323153 is an equidigital number, since it uses as much as digits as its factorization.
10311323153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 10311323153 its reverse (35132311301), we get a palindrome (45443634454).
The spelling of 10311323153 in words is "ten billion, three hundred eleven million, three hundred twenty-three thousand, one hundred fifty-three".
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