10311341134111 has 2 divisors, whose sum is σ = 10311341134112. Its totient is φ = 10311341134110.

The previous prime is 10311341134103. The next prime is 10311341134147. The reversal of 10311341134111 is 11143114311301.

10311341134111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10311341134111 - 2³ = 10311341134103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10311341134151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155670567055 + 5155670567056.

It is an arithmetic number, because the mean of its divisors is an integer number (5155670567056).

Almost surely, 2^{10311341134111} is an apocalyptic number.

10311341134111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10311341134111 is an equidigital number, since it uses as much as digits as its factorization.

10311341134111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 10311341134111 its reverse (11143114311301), we get a palindrome (21454455445412).

The spelling of 10311341134111 in words is "ten trillion, three hundred eleven billion, three hundred forty-one million, one hundred thirty-four thousand, one hundred eleven".