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103120311323 = 1657304920411
BaseRepresentation
bin110000000001001110…
…0110001010000011011
3100212011122001120200202
41200002130301100123
53142142244430243
6115212310052415
710310263120031
oct1400234612033
9325148046622
10103120311323
113a807800197
1217b9a94a10b
1399550c97c3
144dc3624551
152a381464b8
hex180273141b

103120311323 has 8 divisors (see below), whose sum is σ = 103221442800. Its totient is φ = 103019230080.

The previous prime is 103120311299. The next prime is 103120311341. The reversal of 103120311323 is 323113021301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103120311323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103120311295 and 103120311304.

It is not an unprimeable number, because it can be changed into a prime (103120311223) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5041988 + ... + 5062398.

It is an arithmetic number, because the mean of its divisors is an integer number (12902680350).

Almost surely, 2103120311323 is an apocalyptic number.

103120311323 is a deficient number, since it is larger than the sum of its proper divisors (101131477).

103120311323 is a wasteful number, since it uses less digits than its factorization.

103120311323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25117.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 103120311323 its reverse (323113021301), we get a palindrome (426233332624).

The spelling of 103120311323 in words is "one hundred three billion, one hundred twenty million, three hundred eleven thousand, three hundred twenty-three".

Divisors: 1 1657 3049 20411 5052193 33821027 62233139 103120311323