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10312040125123 = 11937458193193
BaseRepresentation
bin1001011000001111010101…
…1111010001001011000011
31100111211011210210000020121
42112003311133101023003
52322423024233000443
633533141423521111
72113006652552362
oct226036537211303
940454153700217
1010312040125123
1133163478a8550
1211a6661459197
1359a56252a409
142791693357d9
1512d38e64b4ed
hex960f57d12c3

10312040125123 has 4 divisors (see below), whose sum is σ = 11249498318328. Its totient is φ = 9374581931920.

The previous prime is 10312040125073. The next prime is 10312040125147. The reversal of 10312040125123 is 32152104021301.

10312040125123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10312040125123 - 233 = 10303450190531 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10312040135123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468729096586 + ... + 468729096607.

It is an arithmetic number, because the mean of its divisors is an integer number (2812374579582).

Almost surely, 210312040125123 is an apocalyptic number.

10312040125123 is a deficient number, since it is larger than the sum of its proper divisors (937458193205).

10312040125123 is an equidigital number, since it uses as much as digits as its factorization.

10312040125123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 937458193204.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 10312040125123 its reverse (32152104021301), we get a palindrome (42464144146424).

The spelling of 10312040125123 in words is "ten trillion, three hundred twelve billion, forty million, one hundred twenty-five thousand, one hundred twenty-three".

Divisors: 1 11 937458193193 10312040125123