103121013001 has 4 divisors (see below), whose sum is σ = 103121774352. Its totient is φ = 103120251652.

The previous prime is 103121012993. The next prime is 103121013011. The reversal of 103121013001 is 100310121301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 103121013001 - 2³ = 103121012993 is a prime.

It is a super-3 number, since 3×103121013001³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103121013011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116311 + ... + 468796.

It is an arithmetic number, because the mean of its divisors is an integer number (25780443588).

Almost surely, 2^103121013001 is an apocalyptic number.

It is an amenable number.

103121013001 is a deficient number, since it is larger than the sum of its proper divisors (761351).

103121013001 is an equidigital number, since it uses as much as digits as its factorization.

103121013001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 761350.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 103121013001 its reverse (100310121301), we get a palindrome (203431134302).

The spelling of 103121013001 in words is "one hundred three billion, one hundred twenty-one million, thirteen thousand, one".