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1031210320202 = 2515605160101
BaseRepresentation
bin11110000000110001110…
…11001100000101001010
310122120201211010222001022
433000120323030011022
5113343404320221302
62105421555552442
7134334232045136
oct17003073140512
93576654128038
101031210320202
11368374384457
12147a322bb722
137632032962a
1437ca750a3c6
151bc567688a2
hexf018ecc14a

1031210320202 has 4 divisors (see below), whose sum is σ = 1546815480306. Its totient is φ = 515605160100.

The previous prime is 1031210320171. The next prime is 1031210320219. The reversal of 1031210320202 is 2020230121301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1020885931321 + 10324388881 = 1010389^2 + 101609^2 .

It is a super-2 number, since 2×10312103202022 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257802580049 + ... + 257802580052.

Almost surely, 21031210320202 is an apocalyptic number.

1031210320202 is a deficient number, since it is larger than the sum of its proper divisors (515605160104).

1031210320202 is an equidigital number, since it uses as much as digits as its factorization.

1031210320202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 515605160103.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1031210320202 its reverse (2020230121301), we get a palindrome (3051440441503).

The spelling of 1031210320202 in words is "one trillion, thirty-one billion, two hundred ten million, three hundred twenty thousand, two hundred two".

Divisors: 1 2 515605160101 1031210320202