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10312113301111 = 21134880318647
BaseRepresentation
bin1001011000001111100111…
…0110011010011001110111
31100111211100220110201211101
42112003321312122121313
52322423202001113421
633533153000150531
72113011531544426
oct226037166323167
940454326421741
1010312113301111
113316385138776
1211a6681a68447
1359a57473b70b
14279174d432bd
1512d395ca3191
hex960f9d9a677

10312113301111 has 4 divisors (see below), whose sum is σ = 10316993621872. Its totient is φ = 10307232980352.

The previous prime is 10312113301097. The next prime is 10312113301121. The reversal of 10312113301111 is 11110331121301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10312113301111 - 223 = 10312104912503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10312113301121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2440157211 + ... + 2440161436.

It is an arithmetic number, because the mean of its divisors is an integer number (2579248405468).

Almost surely, 210312113301111 is an apocalyptic number.

10312113301111 is a deficient number, since it is larger than the sum of its proper divisors (4880320761).

10312113301111 is an equidigital number, since it uses as much as digits as its factorization.

10312113301111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4880320760.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 10312113301111 its reverse (11110331121301), we get a palindrome (21422444422412).

The spelling of 10312113301111 in words is "ten trillion, three hundred twelve billion, one hundred thirteen million, three hundred one thousand, one hundred eleven".

Divisors: 1 2113 4880318647 10312113301111