Base | Representation |
---|---|
bin | 10111011100100111000110… |
… | …101111000101000101000111 |
3 | 111112010021212000100222121121 |
4 | 113130213012233011011013 |
5 | 102004014211213240012 |
6 | 1003153121021254411 |
7 | 30502155365554426 |
oct | 2734470657050507 |
9 | 445107760328547 |
10 | 103121204040007 |
11 | 2a94850335305a |
12 | b6956b6704407 |
13 | 457039843a4ca |
14 | 1b67142d132bd |
15 | bdc644a51a07 |
hex | 5dc9c6bc5147 |
103121204040007 has 2 divisors, whose sum is σ = 103121204040008. Its totient is φ = 103121204040006.
The previous prime is 103121204039947. The next prime is 103121204040119. The reversal of 103121204040007 is 700040402121301.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103121204040007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103121204040307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560602020003 + 51560602020004.
It is an arithmetic number, because the mean of its divisors is an integer number (51560602020004).
Almost surely, 2103121204040007 is an apocalyptic number.
103121204040007 is a deficient number, since it is larger than the sum of its proper divisors (1).
103121204040007 is an equidigital number, since it uses as much as digits as its factorization.
103121204040007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 103121204040007 its reverse (700040402121301), we get a palindrome (803161606161308).
The spelling of 103121204040007 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred four million, forty thousand, seven".
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